Как присвоить диапазон значений переменной в Python?

norm_x = [10, 100]
x = 10.000001

if x >= norm_x[0] and x<= norm_x[1]
    print ("Great")
else:
    print ("Oops")

In [1]: def x_in_bounds(x, bounds): return bounds[0] < x < bounds[1]

In [2]: if x_in_range(1, (0, 2)): print('in')
in

Функция range() если я правильно понял, не удовлетворит мои потребности.

In [7]: 10 in range(1, 11)
Out[7]: True

In [8]: 1 in range(1, 11)
Out[8]: True

In [9]: 11 in range(1, 11)
Out[9]: False

In [12]: %timeit 5 in range(1, 11)
The slowest run took 4.69 times longer than the fastest. This could mean that an intermediate result is being cached.
1000000 loops, best of 3: 348 ns per loop

In [13]: %timeit 1 <= 5 <= 10
10000000 loops, best of 3: 60.2 ns per loop

min_val, max_val = 1, 10

if min_val <= x <= max_val:
    print("...")

def BoundsChecker:
    __init__(self, min_val, max_val):
        self.min_val = min_val
        self.max_val = max_val
        
    def isBounded(self, val):
        return self.min_val <= val <= self.max_val
    
checker = BoundsChecker(1, 10)

if (checker.isBounded(x))
    print("...")

that_list = list(range(1,101))
x = 89
if x in that_list:
    print('cool')

x = 5 # любое число из диапазона
range_nums = range(1, 11) # диапазон: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10. Т.е последнее значений (11) не учитывается

if x in range_nums:
    print(str(x) + " в пределах допустимых значений")
else:
    print(str(x) + " за пределом допустимых значений")