MySql ошибка — mysqli_query() expects parameter 1?

$connection = mysqli_connect($config['db']['server'], $config['db']['username'], $config['db']['password'], $config['db']['name']);
$quere = $data['search_request'];
$type_a = array_shift($type);
mysqli_query($connection, 'SET NAMES utf8');
function search ($query, $type_b) 
{ 
    $query = trim($query); 
    

    
            $q = "SELECT * FROM `remont` WHERE `$type_b` = `$query`";

            $result = mysqli_query($connection, "SELECT * FROM `remont` WHERE $type_b = $query");  //Ругается сюда!!!

            if (mysql_affected_rows() > 0) { 
                $row = mysql_fetch_assoc($result); 
                $num = mysql_num_rows($result);

                $text = '<p>За запитом <b>'.$query.'</b> знайдено співпадінь: '.$num.'</p>';
//$text. '<br>' . 
                 
            } else {
                $text = '<p>За вашим запитом нічого не знайдено( .</p>';
            }
        
    return $text; 
} 
echo search($quere, $type_а);